CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

For the system 3A+2B2C, the expression for equilibrium constant K is:

A
[3A]×[2B][C]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
[A]3×[B][C]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[C]2[A]3×[B]2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
[C][3A]×[2B]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C [C]2[A]3×[B]2
For the reaction:
3A+2B2
Equilibrium constant, K=[C]2[A]3×[B]2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon