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Question

For the system 3A+2B2C, the expression for equilibrium constant K is:

A
[3A]×[2B][C]
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B
[A]3×[B][C]
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C
[C]2[A]3×[B]2
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D
[C][3A]×[2B]
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Solution

The correct option is C [C]2[A]3×[B]2
For the reaction:
3A+2B2
Equilibrium constant, K=[C]2[A]3×[B]2

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