From the following reaction sequence:
$C l_{2} + 2 K O H \to K C l + K C l O + H_{2} O$
$3 K C l O \to 2 K C l + K C l O_{3}$
$4 K C l O_{3} \to 3 K C l O_{4} + K C l$
Calculate the mass of chlorine that reacts with an excess of $K O H$ needed to produce $100 g$ of $K C l O_{4}$ .

195.05 g

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205.05 g

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280.66 g

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328.78 g

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Solution

The correct option is B $205.05 g$
Given reactions:
$4 K C l O_{3} \to 3 K C l O_{4} + K C l$
$12 K C l O \to 8 K C l + 4 K C l O_{3}$
$12 C l_{2} + 24 K O H \to 12 K C l O + 12 H_{2} O + 12 K C l$

Overall reaction: $12 C l_{2} + 24 K O H \to 3 K C l O_{4} + 21 K C l + 12 H_{2} O$

Molar mass of $K C l O_{4} = 138.5 g$
3 mol of $K C l O_{4}$ are formed from 12 mol of $C l_{2}$ .
$3 \times 138.5 g$ of $K C l O_{4}$ is formed from $12 \times 71 g$ of $C l_{2}$ .
So, $100 g$ of $K C l O_{4}$ will be formed = $\frac{12 \times 71 \times 100}{3 \times 138.5} = 205.05 g$ of $C l_{2}$

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Similar questions

Q. From the following reaction sequence:

C l_{2} + 2 K O H \to K C l + K C l O + H_{2} O

3 K C l O \to 2 K C l + K C l O_{3}

4 K C l O_{3} \to 3 K C l O_{4} + K C l

Calculate the mass of chlorine that reacts with an excess of

K O H

needed to produce

100 g

K C l O_{4}

From the following reaction sequence
$C l_{2}$ + 2KOH $\to$ KCl + KClO + $H_{2} O$
3KClO $\to$ 2KCl + $K C l O_{3}$
$4 K C l O_{3}$ $\to$ $3 K C l O_{4} + K C l$

Calculate the mass of chlorine needed to produce 23g of $K C l O_{4}$

From the following reaction sequence
$C l_{2}$ + 2KOH $\to$ KCl + KClO + $H_{2} O$
3KClO $\to$ 2KCl + $K C l O_{3}$
$4 K C l O_{3}$ $\to$ $3 K C l O_{4} + K C l$