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Byju's Answer
Standard XIII
Chemistry
Oxidising Reagent and Reducing Reagent
H2O2 reduces ...
Question
H
2
O
2
reduces
M
n
O
−
4
ion to
A
M
n
+
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B
M
n
2
+
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C
M
n
3
+
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D
M
n
−
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Solution
The correct option is
B
M
n
2
+
2
M
n
O
−
4
+
5
H
2
O
2
+
6
H
+
→
M
n
2
+
+
5
O
2
+
8
H
2
O
.
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0
Similar questions
Q.
M
n
O
−
4
ions can be reduced in strong alkaline medium to give
Q.
100
mL of
H
2
O
2
is oxidised by
100
mL of
0.01
M
K
M
n
O
4
in acidic medium (
M
n
O
⊝
4
reduced to
M
n
2
+
).
100
mL of the same
H
2
O
2
is oxidised by
V
mL of
0.01
M
K
M
n
O
4
in basic medium (
M
n
O
⊝
4
reduced to
M
n
O
2
). Hence,
V
is :
Q.
How many Faraday of electricity is required to reduce
1
mole of
M
n
O
−
4
ions to
M
n
2
+
ions?
Q.
H
2
O
2
reduces
M
n
O
−
4
ion to
Q.
The complete balanced equation is:
M
n
O
2
+
H
2
O
2
→
M
n
O
−
4
+
H
2
O
(Basic medium)
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Standard XIII Chemistry
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