How many moles are there in 220 mg of $C O_{2}$ ?

5 moles

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0.005 moles

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5000 moles

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10 moles

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Solution

The correct option is B 0.005 moles
44 g of $C O_{2}$ = 1 mole
$220 \times 10^{- 3}$ g of $C O_{2} = \frac{(220 \times 10^{- 3})}{44} = 5 \times 10^{- 3} m o l e s = 0.005 m o l e s$

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