How much copper sulphate will be required to saturate 100 g of a dilute aqueous solution of $C u S O_{4}$ at $25^{o} C$ if 10 g of the dilute solution leave on evaporation and drying 1.2 g of anhydrous $C u S O_{4}$ in water at $25^{o} C$ is 25.

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Solution

100 g of dilute solution of $C u S O_{4}$ contain
$= 1.2 \times 10 = 12.0 g C u S O_{4}$
Mass of water present in dilute solution
$= (100 - 12) = 88 g$
To saturate 100 g of water, $C u S O_{4}$ required $= 25 g$
So, to saturate 88 g of water, $C u S O_{4}$ required $= \frac{25}{100} \times 88 = 22 g$
Thus, the mass of $C u S O_{4}$ to be added to 100 g of dilute solution to saturate it $= (22 - 12) = 10 g .$

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