Question 4 (i)

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
The area of the verandah

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Solution

The length of room = 5.5 m and width of the room = 4 m
The length of the room with verandah = 5.5 + 2.25 + 2.25 = 10 m
The width of the room with verandah = 4 + 2.25 + 2.25 = 8.5 m
Area of verandah
= Area of room with verandah - Area of room without verandah
= Area of ABCD - Area of EFGH
$= (A B \times A D) - (E F \times E H)$
$= (10 \times 8.5) - (5.5 \times 4)$
$= 85 - 22$
$= 63 m^{2}$

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Question 4 (i) A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find: The area of the verandah

Question 4 (i)

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
The area of the verandah