Question

If 10 g of ice at $0^{\circ }C$ mixes with 10 g of water at ${10}^{\circ }C$, then the final temperature t is given by

• A. $(10\times 80)+10(t-0)=10(10-t)$
• B. $10\times 80=10(10-t)+10(t-0)$
• C. $t=5^{\circ }C$
• D. $t=0^{\circ }C$

Answer 1

The correct option is D $t=0^{\circ }C$

Required heat to convert ice at $0^{o}C$ to water at $0^{o}C=10\times 80=800cal$

Heat released by water $=10\times 1\times (10-0)=100cal$

Released heat is less than required heat so final temperature is $0^{o}C$.