If $10$ masons working $7$ hours daily can build $28$ water tanks in $16$ days. How many days will $12$ masons working $6$ hours daily take to build $36$ water tanks?

20

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21

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22

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Solution

The correct option is A $20$
$\frac{M_{1} D_{1} H_{1}}{M_{2} D_{2} H_{2}} = \frac{W_{1}}{W_{2}}$
$∴ \frac{10 \times 16 \times 7}{12 \times 6 \times D_{2}} = \frac{28}{36} \Rightarrow D_{2} = \frac{10 \times 16 \times 7 \times 36}{12 \times 6 \times 28} = 20 d a y s$

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