If an equilateral triangle inscribed in a circle with center $O$ , then the measure of $∠ A O B$ is

60

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90

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120

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180

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Solution

The correct option is D $120$

Theorem: Angle subtended by an arc at the centre is double the angle subtended by the same arc at the circumference of a circle
Thus, $∠ A C B = 60^{\circ}$
Hence, $∠ A O B = 120^{\circ}$

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An equilateral ABC is inscribed in a circle with centre O. Then measure of $∠ B O C$ is

An equilateral triangle ABC is inscribed in a circle with centre $O .$ Then, $∠ B O C$ is equal to:

△ A B C

∠ B O C

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