If 2x-1-3x-5 then the value of 5x-6x2-20x-1 is

The correct option is C 1/7 2x+1/3x=15 Multiply both side by 3x #160;Then #160; 6x^2+1=15x Rightarrow 6x^2 15x+1=0 So #160; 5x/6x^ ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Proof by mathematical induction

If 2x+1/3x=...

Question

If $2 x + \frac{1}{3 x} = 5$ then the value of $\frac{5 x}{6 x^{2} + 20 x + 1}$ is

\frac{3}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{7}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{4}{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{1}{7}$
$2 x + \frac{1}{3 x} = 15$ Multiply both side by 3x
Then $6 x^{2} + 1 = 15 x$
$R i g h t a r r o w 6 x^{2} - 15 x + 1 = 0$
So $\frac{5 x}{6 x^{2} + 20 x + 1} = \frac{5 x}{6 x^{2} - 15 x + 1 + 35 x} = \frac{5 x}{0 + 35 x} \Rightarrow \frac{5 x}{35 x} = \frac{1}{7}$

Suggest Corrections

Similar questions

The HCF of 6 (x^{2} - 4) and 15 (x + 2) (x + 7) is :

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve the following equation
(a)

5 x - 11 = 2 x + 7

(b)

3 (x - 8) - 2 (x - 5) = 2 - 5 x

(c)

2 (3 x + 1) - 7 = 2 (6 x - 7)

Q. Solve:

5 x - 2 (2 x - 7) = 2 (3 x - 1) + \frac{7}{2}

Q. Match the equations in List 1 with the solutions in List 2

	List I		List II
A.	${log}_{0.25} {(x^{2} + 2 x - 8)}^{2}$ $- {log}_{0.5} (10 + 3 x - x^{2}) = 1$	1.	${- 3}$
B.	${log}_{2} (x^{2} + 7)$ $= 5 + {log}_{2} x$ $- \frac{6}{{log}_{2} (x + \frac{7}{x})}$	2.	${\frac{1}{4}}$
C.	${log}_{(1 - 2 x)} (6 x^{2} - 5 x + 1)$ $- {log}_{(1 - 3 x)} (4 x^{2} - 4 x + 1) = 2$	3.	${\frac{1}{6} (\sqrt{313} - 1), \frac{1}{2} (\sqrt{73} - 7)}$
D.	${log}_{10} (1 {+ x}^{2} - 2 x) + 1 - {log}_{10} (1 + x^{2}) =$ $2 {log}_{10} (1 - x)$	4.	${1, 7}$

Join BYJU'S Learning Program

If 2x+13x=5 then the value of 5x6x2+20x+1 is

The correct option is C 172x+13x=15 Multiply both side by 3x Then 6x2+1=15xRightarrow6x2−15x+1=0So 5x6x2+20x+1=5x6x2−15x+1+35x=5x0+35x⇒5x35x=17

If $2 x + \frac{1}{3 x} = 5$ then the value of $\frac{5 x}{6 x^{2} + 20 x + 1}$ is