Question

Question 4 (ii)

A verandah of width 2.25 m is constructed all along outside a room which is 5.5 m long and 4 m wide. Find:
The cost of cementing the floor of the verandah at the rate of ₹200 per $m^2$.

Answer 1

The length of room = 5.5 m and width of the room = 4 m
The length of the room with verandah = 5.5 + 2.25 + 2.25 = 10 m
The width of the room with verandah = 4 + 2.25 + 2.25 = 8.5 m
Area of verandah
= Area of room with verandah - Area of room without verandah
= Area of ABCD - Area of EFGH
$=(AB\times AD)-(EF\times EH)$
$=(10\times 8.5)-(5.5\times 4)$
$=85-22$
$=63m^2$

The cost of cementing 1 $m^2$ floor of the verandah = ₹ 200
The cost of cementing 63 $m^2$ floor of the verandah = 200 $\times$ 63 = ₹ 12,600