Question

In a cricket match, a batsman hits boundary 10 times out of 50 balls. what is the probability that he doesn't hit boundary?

• A. 1
• B. 0.5
• C. 0.8
• D. 0.75

Answer 1

Answer: (C)

0.8

The number of balls the batsman played = 50

So total number of trails = 50

Number of balls he hit boundary = 10

$\therefore$ Number of balls he doesn't hit boundary = 50-10

= 40

$\because$ Probability = $\frac{\text{Number of favourable outcome}}{\text{total number of trails}}$

$\therefore$ Probability not to hit boundary = $\frac{40}{50}$

= $\frac{4}{5}$

= $0.8$