Question

In a one-day cricket match, a batsman hits the boundary 8 times out of the 48 balls that he faced. Find the probability that he does not hit the boundary.

Answer 1

Total number of balls faced by the batsman = 48
Number of times the batsman hits the boundary = 8
Number of times the he does not hit the boundary = (48 − 8 ) = 40

Let E be the event that the batsman does not hit the boundary.

∴ Required probability = P(E) = $\frac{40}{48}=\frac{5}{6}$2832 = 78