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Question

In the electric circuit shown in the figure, potential difference across 4 Ω resistance is :

79967_6703034a96f945e39b2e0601e1c60f09.png

A
4V.
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B
2V
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C
1V
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D
6V
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Solution

The correct option is C 4V.
The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.
Rp=(8×8)(8+8)=4ohms

This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then

Rt=R1+Rp=4+4=8ohms.

Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,

I=VR=88=1A.

Hence, the current flowing through the resistor R1 (4 ohms) is 1A.

Now the potential difference across the resistor R1 (4 ohms) is given as follows.

V=IR=1×4=4V

Hence, the potential difference across the resistor R1 (4 ohms) = 4V.

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