wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

In the electric circuit shown in the figure, potential difference across 4 Ω resistance is :

79967_6703034a96f945e39b2e0601e1c60f09.png

A
4V.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4V.
The circuit can be reduced, step by step, to a single equivalent resistance. The 8 ohm and the 8 ohm are connected in parallel , and so they can be replaced by an equivalent resistor Rp of 4 ohms, using the below equation.
Rp=(8×8)(8+8)=4ohms

This resistor is connected in series with the 4 ohm resistor R1. The total resistance Rt of the circuit is then

Rt=R1+Rp=4+4=8ohms.

Since the 4 ohm and the 4 ohm are connected in series, they have the same current I1, which must be equal to the current of the battery. Using Ohms law we get,

I=VR=88=1A.

Hence, the current flowing through the resistor R1 (4 ohms) is 1A.

Now the potential difference across the resistor R1 (4 ohms) is given as follows.

V=IR=1×4=4V

Hence, the potential difference across the resistor R1 (4 ohms) = 4V.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cell and Cell Combinations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon