In the ionic equation for the reaction: IO−3+H++ae−→I−+H2O
the value of 'a' is
A
2
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B
4
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C
6
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D
10
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Solution
The correct option is C 6 This is a reduction reaciton where the oxidation number of I changes from +5 to -1.
Step -1 Balance atoms other than H and O IO−3→I−
Step -2 Balance O IO−3→I−+3H2O
Step -3 Balance H IO−3+6H+→I−+3H2O
Step -4 Balance Charge IO−3+6H++6e−→I−+3H2O