Question 94 (k)
Taking x=−49,y=512 and z=718, find
x−(y+z)
Given, x=−49,y=512 and z=718
Here, x−(y+z)=−49−(512+718)=−49−(5×3+7×236)=−49−(15+1436) [∵ LCM of 12 and 18 = 36]
=−49−2936=−4×4−2936=−16−2936 [∵ LCM of 9 and 36 = 36]
=−4536=−54