Question

# KClO4 is obtained from the following sequence of reactions: Cl2+2KOH→KCl+KClO+H2O 3KClO→2KCl+KClO3 4KClO3→KCl+3KClO4. The correct statement among the following is/are

A
To produce 0.1 mole of KClO4 , 8.96 L of Cl2 at STP is required.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
If the yield of the each reaction is 80%, then moles of KClO4 produced from 1.2 moles of Cl2 will be 0.1536
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Total moles of KCl formed from 1.2 moles of Cl2 will be 2.1 moles of KCl
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Total moles of KCl formed from 53.76 L of Cl2 at STP will be 4.2 moles
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct options are A To produce 0.1 mole of KClO4 , 8.96 L of Cl2 at STP is required. B If the yield of the each reaction is 80%, then moles of KClO4 produced from 1.2 moles of Cl2 will be 0.1536 C Total moles of KCl formed from 1.2 moles of Cl2 will be 2.1 moles of KCl D Total moles of KCl formed from 53.76 L of Cl2 at STP will be 4.2 moles 12Cl2+24KOH→21KCl+3KClO4+12H2O A) From stoichiometry, 12×22.4 gives 3 moles of KClO4 Volume of Cl2 required to form 0.1 moles of KClO4 produced = 112×22.43×0.1=8.96 L B) 12Cl2+24KOH→12KCl+12KClO+12H2O 12KClO→8KCl+4KClO3 4KClO3→KCl+3KClO4 12 moles of Cl2 gives 12 moles of KClO moles of KClO that can be obtained from 1.2 moles of Cl2 = 1.2 Yield of the reaction is 80 % Hence moles that can be obtained =0.8×1.2=0.96 12 moles of KClO gives 4 moles of KClO3 moles of KClO3 that can be obtained from 0.96 moles of KClO =4×0.9612=0.32 Yield of the reaction is 80 %. Hence the actual number of moles 0.8×0.32=0.256 4 moles of KClO3 gives 3 moles of KClO4 Hence moles of KClO4 that can be obtained from 0.256 moles of KClO3 = 3×0.2564=0.192 Yield of the reaction is 80%. Hence actual moles of KClO4 that can be obtained=0.192×0.8=0.1536 C) 12 moles of Cl2 gives 21 moles of KCl and hence 1.2 moles gives 2.1 moles of KCl D) volume of Cl2 required to form 4.2 moles of KCl produced = 112×22.421×4.2=53.76 L

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program