Question

lf a simple pendulum oscillates with an amplitude of $50mm$ and time period of $2$ sec then its maximum velocity is

• A. $0.6m/s$
• B. $0.16m/s$
• C. $0.8m/s$
• D. $0.32m/s$

Answer 1

The correct option is B $0.16m/s$

$v=\omega \sqrt{a^2-u^2}$; when $u=0,v=v_{max}$
So, $v_{max}=\omega a$
$[$Where $\omega$ is angular velocity and $a$ is amplitude$]$
$v_{max}=\frac{2\pi }{T}\times a=\frac{2\pi }{2}\times \frac{50}{1000}=0.16m/sec$