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x and y vary directly. When x = 3, then y = 36. What will be the value of x when y = 96?
(a) 18
(b) 12
(c) 8
(d) 4

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Solution

(c) 8

$x$ 3 $x_{1}$

$y$ 36 96

$x and y var y directly . Then x = k y, where k is the constant of proportionality . \Rightarrow k = \frac{x}{y} Now, \frac{3}{36} = \frac{x_{1}}{96} \Rightarrow \frac{96 \times 3}{36} = x_{1} \Rightarrow 8 = x_{1}$

∴ Value of $x = 8$

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Question 10
Let y varies directly as x. if y = 12 when x = 4, then write a linear equation. What is the value of y when x = 5?

Question 10
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