Question

An ideal gas occupies a volume of $2{\text{m}}^3$at a pressure of $3\times {10}^6\text{Pa}$. The energy of the gas :

• A. $9\times {10}^6\text{J}$
• B. $3\times {10}^2\text{J}$
• C. $6\times {10}^4\text{J}$
• D. ${10}^8\text{J}$

Answer 1

The correct option is A $9\times {10}^6\text{J}$

Energy of the ideal gas, $E$

$=\frac{f}{2}nRT=\frac{3}{2}PV$

$=\frac{f}{2}(3\times {10}^6)\left(2\right)=f\times 3\times {10}^6$

Considering gas as monoatomic i. e., $f=3$

So, energy, $E=9\times {10}^6\text{J}$