On being strongly heated, Potassium Chlorate gives Potassium Chloride and Oxygen.

True

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False

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Solution

The correct option is A True
The above statement is true because Potassium Chlorate( ${KClO}_{3}$ ) decomposes when heated, giving oxygen( $O_{2}$ ) and Potassium chloride( $KCl$ ).
Chemical equation :
$2 {KClO}_{3} (s) \overset{}{\overset{∆}{\to} 2 KCl (s) + {CO}_{2}} (g)$

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Similar questions

Q. Potassium chlorate decomposes, on heating, to form potassium chloride and oxygen. When 24.5 g of potassium chlorate is decomposed completely, then 14.9 g of potassium chloride is formed. Calculate the mass of oxygen formed. Which law of chemical combination have you used in solving this problem?

Q. Potassium chlorate

(K C l O_{3})

on heating gives potassium chloride and oxygen. Write a balanced for this reaction and indicate the evolution of gas.

Q. What mass of potassium chlorate

(K C l O_{3})

on heating gives 1.491 g of potassium chloride (KCl) and 0.672 litres of oxygen at NTP?

Potassium chlorate decomposes, on heating , to form potassium chloride and oxygen. When 24.5g of potassium chlorate is decomposes completely then 14.9g of potassium chloride is formed . Calculate the mass of oxygen formed . State the law of chemical combination which you have used in solving this problem?

Q. Oxygen is prepared by catalytic; decomposition of potassium chlorate

(K C l O_{3})

. Decomposition, of potassium chlorate gives potassium chloride

(K C l)

and oxygen

(O_{2})

. How many moles and how many grams of

K C l O_{3}

are required to produce 2.4 mole

O_{2}

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On being strongly heated, Potassium Chlorate gives Potassium Chloride and Oxygen.

The correct option is A TrueThe above statement is true because Potassium Chlorate(KClO3) decomposes when heated, giving oxygen(O2) and Potassium chloride(KCl).Chemical equation :2KClO3(s)→∆2KCl(s)+CO2(g)

The correct option is A True
The above statement is true because Potassium Chlorate( ${KClO}_{3}$ ) decomposes when heated, giving oxygen( $O_{2}$ ) and Potassium chloride( $KCl$ ).
Chemical equation :
$2 {KClO}_{3} (s) \overset{}{\overset{∆}{\to} 2 KCl (s) + {CO}_{2}} (g)$