On hydrolysis , $X e F_{4}$ produces:

X e F_{6}

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X e O_{3}

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X e O

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X e

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Solution

The correct options are
B $X e$
D $X e O_{3}$
$6 X e F_{4} + 12 H_{2} O ⟶ 2 X e O_{3} + 4 X e + 3 O_{2} + 24 H F$
$X e F_{4}$ forms different product compare to $X e F_{2}$ & $X e F_{6}$

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