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Question

# On the surface of the earth at 1 atm pressure, a balloon filled with H2 gas occupies 500 mL, the volume being 5/6 of its maximum capacity. The balloon is left in air. It starts rising. The height above which the balloon will burst if temperature of the atmosphere remains constant and the pressure decreases by 1 mm of Hg for every 100 cm rise of height is?

A
120 m
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B
136.67 m
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C
126.67 m
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D
100 m
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Solution

## The correct option is C 126.67 mAccording to Boyle's Law: P1V1=P2V2 P1=1 atm=760 mm,V1=500 mL P2=?,V2=? Now, let x be maximum volume 500=56x, x=600 mL Since balloon will burst at 600 mL (∵Vmax) V2=600 mL Now, as Boyle's law: 760×500=P2×600 P2=633.33 mm Pressure decreased =760−633.33=126.67 mm Now, 1 mm dec.→100 cm 126.67 mm dec.→100×126.67=12667 cm=126.67 m

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