If 17^th term of an A.P. exceeds its 10^th term by 7. Find the common difference.

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Solution

We know that,

For an A.P., a_n = a + (n − 1) d

a₁₇ = a + (17 − 1) d

a₁₇ = a + 16d

Similarly, a₁₀ = a + 9d

It is given that

a₁₇ − a₁₀ = 7

(a + 16d) − (a + 9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.

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