Q30 motion
Q. A moving train is stopped by applying brakes. It stops after travelling 80 m. If the speed of the train is doubled and retardation remains the same, it will cover a distance -
(1) same as earlier
(2) double the distance covered earlier
(3) four times the distance covered earlier
(4) half the distance covered earlier

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Solution

Dear Student

$v^{2} - u^{2} = 2 a S l e t f i n a l v e l o c i t y = 0 - u^{2} = 2 a S S = \frac{- u^{2}}{2 a} I f s p e e d i s d o u b l e d a n d r e t a r d a t i o n i s s a m e t h a n D i s \tan c e t r a v e l l e d w i l l b e c o m e f o u r t i m e s t h e d i s \tan c e c o v e r e d e a r l i e r . R E G A R D S$

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Dear Student v2-u2=2aSlet final velocity=0-u2=2aSS=-u22aIf speed is doubled and retardation is same thanDistance travelled will become four times the distance covered earlier.REGARDS