Question

Resistance 1 $\Omega$, 2 $\Omega$ and 3 $\Omega$ are connected to form a triangle. If a 1.5 V cell of negligible internal resistance is connected across the 3 $\Omega$ resistor, the current flowing through the resistor will be

• A. 0.25 A
• B. 0.5 A
• C. 1.0 A
• D. 1.5 A

Answer 1

The correct option is B 0.5 A

Here resistors 1 and 2 in series and combine (1,2) in parallel with 3. So, potential across (1,2) and 3 will be same i.e $1.5V$
Thus, current through $3\Omega =\frac{1.5}{3}=0.5A$