Question

Say true or false:

If $y^2-3=0$, then $y=\pm \sqrt{3}$.

• A. True
• B. False

Answer 1

The correct option is A True

$y^2-3=0$

By using formula $a^2-b^2=(a+b)(a-b)$
$\therefore y^2-(\sqrt{3}{)}^2=(y+\sqrt{3}\left)\right(y-\sqrt{3})=0$

$\therefore y=\pm \sqrt{3}$