Question

Sum of 3 consecutive multiples of 6 is 666. Find the multiples

Answer 1

Let the first multiple of 6 be x
Second multiple = x+6
Third multiple = x+6+6 = x+12
According to Question:
x+x+6+x+12 = 666
=>3x + 18 = 666
=>3x = 666-18 = 648
=>x = 648/3
=>x = 216
x+6 = 222
x+12 = 228

So, the multiples are 216, 222 and 228.