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Question

Suppose x,y,z >0 and are not equal to 1 and logx+logy+logz=0. What is the value of x1logy+1logz×y1logz+1logx×z1logx+1logy.
(All log functions have base 10)

A
103
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B
104
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C
102
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D
none of these
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Solution

The correct option is A 103
Let, K=x1logy+1logz×y1logz+1logx×z1logx+1logy
Taking log on both the sides,
logK=logx[1logy+1logz]+logy[1logz+1logx]+logz[1logx+1logy](i)

Putting logx+logy+logz=0 (given), we get

logxlogy+logzlogy=1;logylogx+logzlogx=1;logxlogz+logylogz=1
R.H.S. of Eq.(i)=3
log10K=3 or K=103

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