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Question

Taxi charges in a city consisting of fixed charges and the remaining depending upon the distance travelled in kilometres. If a man travels 80 km, he pays Rs.1330, and travelling 90 km, he pays Rs.1490.Find the fixed charges and rate per km.

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Solution

Let fixed charges be x
Let the charge for per km be y
1st eq. will be
x+80y=1330
2nd eq.will be
x+90y=1490
By elimination method
x+80y=1330------(1)
x+90y=1490------(2)
eq (2) - eq (1)
we get
10y= 160
y= 1606
y=16
so,charge per km=16
put the value of y put on equation(1)
then
x plus 80 cross times 16 equals 1330 x plus 1280 equals 1330 x equals 50
the fixed charge is Rs 50


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