Taxi charges in a city consisting of fixed charges and the remaining depending upon the distance travelled in kilometres. If a man travels 80 km, he pays Rs.1330, and travelling 90 km, he pays Rs.1490.Find the fixed charges and rate per km.
Let fixed charges be x
Let the charge for per km be y
1st eq. will be
x+80y=1330
2nd eq.will be
x+90y=1490
By elimination method
x+80y=1330------(1)
x+90y=1490------(2)
eq (2) - eq (1)
we get
10y= 160
y= 1606
y=16
so,charge per km=16
put the value of y put on equation(1)
then
the fixed charge is Rs 50