Let the fixed taxi charges per day be Rs. x and the charges for travelling one km be Rs. y.
It is given that for travelling 110 km, a person pays Rs. 1130.
∴ Rs. x + Rs. 110y = Rs. 1130
⇒ (x + 110y) = 1130 ....(i)
Again, it is given that for travelling 200 km, a person pays Rs. 1850.
∴ Rs. x + Rs. 200y = Rs. 1850
⇒ (x + 200y) = 1850 ....(ii)
On subtracting (i) from (ii), we get:
90y = 720
⇒ y = 8
On substituting y = 8 in (i), we get:
x + 110 × 8 = 1130
⇒ x = (1130 − 880) = 250
Hence, the fixed charges per day is Rs. 250 and the rate per km is Rs. 8.