Question

The angle of projection at which the horizontal range and maximum height of projectile are equal is:

• A. ${45}^o$
• B. ${60}^o$
• C. $\theta ={\tan }^{-1}\left(4\right)$
• D. $\theta ={\tan }^{-1}\left(0.25\right)$

Answer 1

Answer: (C)

$\theta ={\tan }^{-1}\left(4\right)$

According to question,

$Range=Maximumheight$

$R=H$

$\frac{2u^{2}sin\theta cos\theta }{g}=\frac{u^{2}si{n}^2\theta }{2g}$

$2cos\theta =\frac{sin\theta }{2}$

$tan\theta =4$

$\theta =ta{n}^{-1}\left(4\right)$

The correct option is C.