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Alpha Decay

The binding e...

Question

The binding energy per nucleon for $C^{12}$ is $7.68$ MeV and that for $C^{13}$ is $7.47$ MeV. What is the energy required to remove a neutron from $C^{13}$ ?

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Solution

Initially atom is $C^{13}$ and finally $C^{12}$
So, energy released or required to remove a neutron will be difference of initial and final energy.
$E = E_{f} - E_{i} E = 7.68 - 7.47 E = 0.21 M e V$

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