Question

The boiling point of $CC{l}_4$ is higher than that of $CHC{l}_3$ because :

• A. the dipole moment of $CC{l}_4$ is greater than that of $CHC{l}_3$
• B. $CC{l}_4$ forms hydrogen bonds.
• C. $CC{l}_4$ has higher molecular mass than that of $CHC{l}_3$
• D. $CC{l}_4$ is more ionic than $CHC{l}_3$

Answer 1

The correct option is C $CC{l}_4$ has higher molecular mass than that of $CHC{l}_3$

Molecular mass $\propto$ strength of vander Waal's force $\propto$ boiling point.
Boiling point of $CHC{l}_3={61}^{\circ }C$ and $CC{l}_4={73}^{\circ }C$