The current in a circuit containing a battery connected to 2 Ωresistance is 0.9 A. When a resistance of 7 Ωconnected to the same battery, the current observed in the circuit is 0.3 A. Then the internal resistance of the battery is
A
0.1Ω
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B
0.5Ω
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C
1Ω
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D
Zero
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Solution
The correct option is B 0.5Ω case 1 :- E=0.9(R+r) E=0.9(2+r) case 2:- E=0.3(R+r) E=0.3(7+r) ⇒0.9(2+r)=0.3(7+r) 6+3r=7+r 2r=1 r=0.5Ω