Question

The dimensions of the floor of a rectangular hall are $4m\times 3m$. The floor of the hall is to be fully with $8cm\times 6cm$ rectangular tiles without breaking tiles to smaller size. Find the number of tiles required.

Answer 1

STEP: Find the number of tiles required

Area of floor of a rectangular hall $=4m\times 3m$

$=12m^{2^{}}$

Area of rectangular tiles $=8cm\times 6cm$

$=0.08m\times 0.06m$

$\Rightarrow$Number of tiles required $=\frac{\mathrm{Area}\mathrm{of}\mathrm{floor}\mathrm{of}\mathrm{a}\mathrm{rectangular}\mathrm{hall}}{Areaofrec\tan gulartiles}$

$=\frac{12}{0.08\times 0.06}$

$=\frac{12\times 100\times 100}{8\times 6}=2500$

Therefore, the number of tiles required are $2500$ .