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The dissociation constant of two acids HA1 and  HA2  are  3.14 × 104 and 1.96 × 105 respectively. The relative strength of the acids will be approximately 


  1. 1:4

  2. 4:1

  3. 1:16

  4. 16:1


Solution

The correct option is B

4:1


α1α2 = Ka1Ka2 = 3.14 × 1041.6 × 105 = 4 : 1

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