Question

# The electric field in a region is given by →E=25E0^i+35E0^j with E0=4.0×103 N/C. The flux of this field through a rectangular surface area 0.4 m2 parallel to Y– Z plane is (in Nm2C−1)

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Solution

## Since rectangular surface area is parallel to Y-Z plane, so flux of the j component of the field through it will be zero. From definition of electric flux: ϕ=∮→E.−→dA ϕ=25E0×(0.4) ϕ=25×4×103×0.4 ϕ=640 Nm2C−1

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