The external diameter of a closed wooden box are $27 c m, 19 c m$ and $11 c m$ . If the thickness of the wood in the box is $1.5 c m$ , find:
Number of $4 c m$ cubes that could be placed into the box.

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Solution

External volume of the box =27×19×11 cm2=5643 cm3
Since, external dimensions are 27 cm.19 cm,11 cm
Thickness of the wood is =1.5 cm
Internal simensions =(27−2×1.5)cm,(19−2×1.5)cm,(11−2×1.5)cm
=24cm,16cm,8cm
Hence internal volume of box =(24×16×8) cm3=3072 cm3
Volume of 4 cm cube =53=64 cm3
Number of 4 cm cubes be placed into the box =3072/64=48

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The external diameter of a closed wooden box are 27 cm,19 cm and 11 cm. If the thickness of the wood in the box is 1.5 cm, find:Number of 4 cm cubes that could be placed into the box.

The external diameter of a closed wooden box are $27 c m, 19 c m$ and $11 c m$ . If the thickness of the wood in the box is $1.5 c m$ , find:
Number of $4 c m$ cubes that could be placed into the box.