The frictional force due to air on a body of mass $0.25 k g$ falling with an acceleration of $9.2 {m s}^{- 2}$ will be:

0.15 N

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1.5 N

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15 N

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z e r o

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Solution

The correct option is A $0.15 N$
From FBD, $m a = m g - f$
or $f = m (g - a) = 0.25 (9.8 - 9.2)$ take $g = 9.8 m / s^{2}$
$∴ f = 0.15 N$

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