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Conductivity MP BP and Electronegativity (Group 2)

The gas turns...

Question

The gas turns lime water milky. It reacts with potassium dichromate paper and turns the paper from orange to green. Guess the anion.

A

C O_{3}^{2 -}

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B

C l^{-}

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C

B r^{-}

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D

S O_{3}^{2 -}

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Solution

The correct option is D $S O_{3}^{2 -}$
The anion which turns lime water milky and turns potassium dichromate paper from orange to green is sulphate ions.

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Similar questions

Q. A salt on reaction with dil.

H_{2} S O_{4}

produces a colourless gas which turns lime water milky and an acidified orange coloured potassium dichromate solution green. The salt may be:

Q. When a mixture

(A)

of unknown gases is passed into the dichromate solution, then orange color turns to green; when the solution is boiled and gas passed into lime water, then lime water turns milky. Find out

(A)

.

Q. Identify the anion present in the following compounds:
Compound

Z

which on reacting with dilute sulphuric acid liberates a gas which turns lime water milky, but the gas has no effect on acidified potassium dichromate solution.

Q. A mixture contains,

{C O}_{3}^{2 -}

{S O}_{3}^{2 -}

{S O}_{4}^{2 -}

.
If scheme given to identify above unknowns is true enter 1, if false enter 0.
Add dil.

H C l

, brisk reaction with pungent odour gas indicates

{S O}_{3}^{2 -}

{C O}_{3}^{2 -}

, pungent gas is

{S O}_{2}

K_{2} {C r}_{2} O_{7}

solution. If mixture turns green then

{S O}_{3}^{2 -}

is confirmed. Pass the evolved gas into lime water, if it turns milky,

{C O}_{3}^{2 -}

Q. A salt D on treatment with dilute sulphuric acid produces a gas which turns lime water milky but has no effect on acidified potassium dichromate solution.Identify the anion present in the compound?

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