The length of a hall is 18 m and its width is 13.5 m. Find the least number of square tiles, each of side 25 cm, required to cover the floor of the hall, without leaving any of the margin.

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Solution

Area of the hall $= l \times b = 18 \times 135 = 2430 m^{2}$
Area of each square tile $= a^{2} = 25^{2} = 625 s q c m = 0.625 s q m$
Number of tiles required $= \frac{A r e a o f t h e h a l l}{A r e a o f e a c h s q u a r e t i l e} = \frac{2430}{0.625} = 3888$

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The length of a hall is 18 m and its width is 13.5 m. Find the least number of square tiles, each of side 25 cm, required to cover the floor of the hall, without leaving any of the margin.

Area of the hall =l×b=18×135=2430m2Area of each square tile =a2=252=625sqcm=0.625sqmNumber of tiles required =AreaofthehallAreaofeachsquaretile=24300.625=3888

Area of the hall $= l \times b = 18 \times 135 = 2430 m^{2}$
Area of each square tile $= a^{2} = 25^{2} = 625 s q c m = 0.625 s q m$
Number of tiles required $= \frac{A r e a o f t h e h a l l}{A r e a o f e a c h s q u a r e t i l e} = \frac{2430}{0.625} = 3888$