The magnetic poles placed in air repel each other with a force of $4 \times 10^{- 6} N$ . When the space between them is filled with a medium the repulsive force becomes $2.24 \times 1 0^{- 5} N$ . The relative permeability of the medium is

\frac{5}{28}

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5.6

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8.96 \times 10^{- 11}

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56

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Solution

The correct option is B $5.6$
$F = 4 \times 10^{- 6} N$
$F_{n e w} = 2.24 \times 10^{- 5}$
$F \times M_{2} = F_{n e w}$ Here M is the permeability.
$M_{2} = \frac{2.24 \times 10^{- 5}}{4 \times 10^{- 6}}$
$M_{2} = 5.6$

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The magnetic poles placed in air repel each other with a force of 4×10−6N. When the space between them is filled with a medium the repulsive force becomes 2.24×10−5N. The relative permeability of the medium is

The correct option is B 5.6F=4×10−6NFnew=2.24×10−5F×M2=Fnew Here M is the permeability.M2=2.24×10−54×10−6M2=5.6

The magnetic poles placed in air repel each other with a force of $4 \times 10^{- 6} N$ . When the space between them is filled with a medium the repulsive force becomes $2.24 \times 1 0^{- 5} N$ . The relative permeability of the medium is

The correct option is B $5.6$
$F = 4 \times 10^{- 6} N$
$F_{n e w} = 2.24 \times 10^{- 5}$
$F \times M_{2} = F_{n e w}$ Here M is the permeability.
$M_{2} = \frac{2.24 \times 10^{- 5}}{4 \times 10^{- 6}}$
$M_{2} = 5.6$