The molar conductivity of a 0.5 mol/dm $^{3}$ solution of $A g N O_{3}$ with electrolytic conductivity of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is :

0.086 S c m^{2} / m o l

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028.8 S c m^{2} / m o l

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2.88 S c m^{2} / m o l

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11.52 S c m^{2} / m o l

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Solution

The correct option is D $11.52 S c m^{2} / m o l$
C is $0.5 m o l / d m^{3}$
$K = 5.76 \times 10^{- 3} S c m^{- 1}$
T=298K
$λ = \frac{K \times 1000}{m}$
$λ = \frac{5.76 \times 10^{- 3}}{0.5}$
$11.52 S c m^{2} / m o l$
Hence option D is correct.

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Similar questions

Q. The molar conductivity of a

0.5 m o l / d m^{3}

solution of

A g N O_{3}

with electrolytic conductivity of

5.76 \times 10^{- 3} S c m^{- 1}

at 298 K is

The molar conductivity of a $0.5 m o l / d m^{3}$ solution of $A g N O_{3}$ with electrolytic conductiviy of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is

Q. The molar conductivity of a

0.5 m o l / d m^{3}

solution of

A g N O_{3}

with electrolytic conductivity of

5.76 \times 10^{- 3} S c m^{- 1}

298 K

is:

The molar conductivity of a $0.5 m o l / d m^{3}$ solution of $A g N O_{3}$ with electrolytic conductiviy of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is

Q. Electrolytic conductivity of

0.3 M

solution of

K C I

298 K

3.72

10^{- 2} S c m^{- 1}

.Calculate its molar conductivity (

S c m^{2} m o l^{- 1}

)

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The molar conductivity of a 0.5 mol/dm3 solution of AgNO3 with electrolytic conductivity of 5.76×10−3Scm−1 at 298 K is :

The correct option is D 11.52 Scm2/molC is 0.5 mol/dm3K=5.76×10−3Scm−1T=298Kλ=K×1000mλ=5.76×10−30.511.52 Scm2/molHence option D is correct.

The molar conductivity of a 0.5 mol/dm $^{3}$ solution of $A g N O_{3}$ with electrolytic conductivity of $5.76 \times 10^{- 3} S c m^{- 1}$ at 298 K is :

The correct option is D $11.52 S c m^{2} / m o l$
C is $0.5 m o l / d m^{3}$
$K = 5.76 \times 10^{- 3} S c m^{- 1}$
T=298K
$λ = \frac{K \times 1000}{m}$
$λ = \frac{5.76 \times 10^{- 3}}{0.5}$
$11.52 S c m^{2} / m o l$
Hence option D is correct.