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Equivalent, Molar Conductivity and Cell Constant

The molar con...

Question

The molar conductivity of a 1.5M solution of an electrolyte is found to be $138.9 s c m^{2} m o l^{- 1}$ . Calculate the conductivity of this solution.

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Solution

Molar Conductivity, $k = \frac{C o n d u c t i v i t y}{C o n c e n t r a t i o n}$
$Λ_{m} = \frac{k}{c}$
Conductivity, $\in\equiv= Λ_{m} \times C$
$= \frac{138.9 (S c m^{2} m o l^{- 1}) \times 1.5 (m o l / L)}{1000 (C M^{3} / L)}$
$= 0.208 S c m^{- 1}$

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