The normality of a solution of sodium hydroxide 100 mL of which contains 4 grams of NaOH is

0.1

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0.4

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Solution

The correct option is C 1
$V o l u m e = 100 m L .$
$M a s s = 4 g r a m .$

$M o l a r i t y = \frac{number of mole of solute}{Volume of solution(L)}$

$N o . o f m o l e s = \frac{4}{40} = 0.1$

$m o l a r i t y = 0.1 / 0.1$

$∴ m o l a r i t y = 1$

$And normality = M o l a r i t y \times n - f a c t o r$

$M o l a r i t y = 1 a n d n - f a c t o r = 1 ( n factor is no.of OH or H ions release by acid or base).$

$∴ n o r m a l i t y = 1$

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