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Question

The number of moles of oxalate ions oxidized by one mole of MnO4 ion in acidic medium.

A
52
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B
25
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C
35
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D
53
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Solution

The correct option is A 52
Using,
Equivalents of C2O24= equivalents of MnO4

Moles×n factor of C2O24=Moles×n factor of MnO4

putting values,

Moles×2=1×5
Moles=52

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