The number of ways in which 52 cards can be divided among 4 players so that each may have 13 is
A
52!(13!)4
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B
52!4!13
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C
52!4!(13!)4
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D
52!13!413
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Solution
The correct option is A52!(13!)4 1st person =52C13 2nd person =39C13 3rd person =26C13 4th person =13C13 Total = 52C13 x 39C13 x 26C13 x 13C13 =52!13!39!×39!13!26!×26!13!13!×13!13!0! Total =52!13!13!13!13!=52!(13!)4