The radii of $F, F^{-}, O$ and $O^{2 -}$ are in the order of

$O^{2 -} > F^{-} > O > F$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$O^{2} - > F^{-} > F > O$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$F^{-} > O^{2 -} > F > O$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$O^{2 -} > O > F^{-} > F$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$O^{2 -} > F^{-} > O > F$

Atomic radius decreases when we go from left to right in a period due to increase in effective nuclear charge. Thus, the size of O > F.

As $O^{2 -}$ and $F^{-}$ are isoelectronic, therefore, size of $O^{2 -} > F^{-}$

Suggest Corrections

Similar questions

The radii of $F, F^{-}, O$ and $O^{2 -}$ are in the order of

The radii of $F, F^{-}, O$ and $O^{- 2}$ are in the order of

N^{3 -}

O^{2 -}

O^{2 -}, F^{-}, N a^{+} and M g^{2 +}

N^{3 -}, O^{2 -}

F^{-}

o A

Join BYJU'S Learning Program