Question

The rate law for the reaction:

RCl + NaOH $\to$ ROH + NaCl is given by;

rate = k[RCl]. The rate of this reaction is

• A. Doubled by doubling the concentration of NaOH
• B. Halved by reducing the concentration of RCl by one half
• C. Increased by increasing the temperature of the reaction
• D. Unaffected by change of temperature

Answer 1

Answer: (B), (C)

The correct options are
B Increased by increasing the temperature of the reaction
C Halved by reducing the concentration of RCl by one half

The rate law expression is $rate=k\left[RCl\right]$

The rate of this reaction is

(A) not doubled by doubling the concentration of $NaOH$ as the rate is independent of the concentration of $NaOH$.

(B) Halved by reducing the concentration of $RCl$ by one-half as the rate is directly proportional to the concentration of $RCl$.
(C) Increased by increasing the temperature of the reaction. The rate of the reaction is directly proportional to temperature.

(D) See reason C above

Thus, the statements (B) and (C) are correct.